string and int concatenation in C++ -

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• how concatenate std::string , int? 26 answers

string words[5]; (int = 0; < 5; ++i) {     words[i] = "word" + i; }  (int = 0; < 5; ++i) {     cout<<words[i]<<endl; } 

i expected result :

word1 . . word5 

bu printed in console:

word ord rd d 

can tell me reason this. sure in java print expected.

c++ not java.

in c++, "word" + i pointer arithmetic, it's not string concatenation. note type of string literal "word" const char[5] (including null character '\0'), decay const char* here. "word" + 0 you'll pointer of type const char* pointing 1st char (i.e. w), "word" + 1 you'll pointer pointing 2nd char (i.e. o), , on.

you use operator+ std::string, , std::to_string (since c++11) here.

words[i] = "word" + std::to_string(i); 

btw: if want word1 ~ word5, should use std::to_string(i + 1) instead of std::to_string(i).