Ruby Key Using Split and Join -


i have written exam here, here's instruction.

write program prints out groups of words anagrams. anagrams words have same exact letters in them in different order. output should this:

["demo", "dome", "mode"] ["neon", "none"]

(etc)

and here's solution this:

words =  ['demo', 'none', 'tied', 'evil', 'dome', 'mode', 'live',           'fowl', 'veil', 'wolf', 'diet', 'vile', 'edit', 'tide',           'flow', 'neon']   result = {}  words.each |word|   key = word.split('').sort.join   if result.has_key?(key)     result[key].push(word)   else     result[key] = [word]   end end  result.each |k, v|   puts "------"   p v end

i've been trying understand ruby code solution can't grasp it. 1 of question how can test result hash if has no key or element contain it. thing how .join , .sort works on code.

i confuse how go thru answer. can out there can explain on codes line line in layman's term beginner dummy me can understand?

i this:

words =  ['demo', 'none', 'tied', 'evil', 'dome', 'mode', 'live',       'fowl', 'veil', 'wolf', 'diet', 'vile', 'edit', 'tide',       'flow', 'neon']  words.group_by { |word| word.chars.sort }.values  #=> [["demo","dome","mode"],["none","neon"],["tied","diet","edit","tide"],["evil","live","veil","vile"],["fowl","wolf","flow"]]

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