python - Finding word overlap in the list -

i need write function given list of words returns true if there repeating words there, or false otherwise.

this first programming attempt , having problem following:

def over(list1):     in list1:         j in list1:             if == j:                 return false         return true 

i expecting, if run this:

over(["alex", "alex"]) 

it must return true since overlap.

if run:

over(["alex", "david"]) 

then must return false since not overlap.

please give me advice on how solve this.

if need count occurrences of list elements using counter collection module

solution(in python 3.2):

from collections import counter def occurdict(items):     dict_ans = dict(counter(items).most_common())     return dict_ans  list=['car', 'bus', 'truck', 'train', 'truck', 'train', 'bus', 'bus', 'train'] print(occurdict(list)) 

output:{'truck': 2, 'car': 1, 'train': 3, 'bus': 3}

and if want check if items occures multiple times then, solution:

from collections import counter def over(items):     l = counter(items).most_common()     if l[0][1] > 1:         return true     else:         return false  list=['car', 'bus', 'truck', 'train', 'truck', 'train', 'bus', 'bus', 'train'] print(over(list)) 

for input: list = ['car', 'bus', 'truck', 'train'] output: false