php number compare Array -

i have student examiner language level
example:
(8,8,9,8,7) repeat number "8" "8"
(7,7,8,9,10) repeat number "7" "7"
(7,8,9,10,9) no repeat number last "9"
(7,7,8,8,9) forget "7" > last repeat number "8"
(7,7,8,9,9) forget "7" >get last repeat number "9"

code here

//get duplicate function getarraydups($array) { $counts = array_count_values($array); return array_filter( $counts, create_function( '$val', 'return($val > 1);' ) ); }

// usage test: $test = array('8','8','7','7','7'); $result = getarraydups($test);     if(count($result))     {       echo "<p>you had 1 or more duplicate entries:</p>\n<ul>\n";     foreach($result $entry => $count)      {    if ($count >= 3){      echo "<li> level  $entry ($count)</li>";    break;      }   echo "<li>  level $entry ($count)</li>";  }  }   else   {   //echo end($test);   echo "<li>no duplicates  level found. last level." . end($test) . "</li>";   } 

wondering if had other ideas how might achieve this.

if (8,8,9,8,7) string can convert array using explode , use array_count_values, if data array (like $arr = [8,8,9,8,7]) directly use array_count_values

so you'd doing like:

<?php     $str = '8,8,9,8,7';     $arr = explode(',', $str);     $arrcount = array_count_values($arr);     $temp= false;     for($i=count($arr)-1;$i> 0;$i--) {         if($arrcount[$arr[$i]] > 1) {            echo "last repeat is: ".$arr[$i];            $temp = true;            break;         }     }     if(!$temp)         echo "no repeat found";  ?>