javascript - Vector: Get closest vectors based on a single vector -

update:

thanks user @thomas able fix script. can find comments in comment section below.

to make easier, here important quotes:

[...] why vectors contain strings instead of numbers?

i accidently kept on using strings in vectors, breaking proper results. make sure not use strings when working numbers.

in addition, make sure results proper sorted:

sort by:

min(||house.min - client||, ||house.max - client||)

or

||(house.max + house.min)/2 - client||

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the problem:

i have array 3 houses, each containing 2 x, y, z vectors. 1 of them min point, whereas other max. 2 vectors represent field/area house in.

in addition, have 1 client represented single vector.

now want closest houses client near to. preferably based on min , max vector of house.

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values:

var houses = [     {         "max": { x: "-7839.9688", y: "-7469.0312", z: "215.537" },         "name": "house 1",         "min": { x: "-7112.0312", y: "-7932.9692", z: "72.0312" }     }, {         "max": { x: "-6380.0312", y: "-9586.1963", z: "372.1475" },         "name": "house 3",         "min": { x: "-6764.2441", y: "-9189.0312", z: "96.3953" },     }, {         "max": { x: "-7747.1074", y: "-8659.9023", z: "422.2812" },         "name": "house 2",         "min": { x: "-6827.3853", y: "-9668.9688", z: "72.0312" },     } ] 

please note: array above not represent figure below. figure illustration purposes only. in particular case, client 1 close house 2. however. in different use-case, he/she might close house 3.

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illustration / figure:

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approach 1:

var houses = [    {      "max": { x: "-7839.9688", y: "-7469.0312", z: "215.537" },      "name": "house 1",      "min": { x: "-7112.0312", y: "-7932.9692", z: "72.0312" }    },     {      "max": { x: "-6380.0312", y: "-9586.1963", z: "372.1475" },      "name": "house 3",      "min": { x: "-6764.2441", y: "-9189.0312", z: "96.3953" },    },    {      "max": { x: "-7747.1074", y: "-8659.9023", z: "422.2812" },      "name": "house 2",      "min": { x: "-6827.3853", y: "-9668.9688", z: "72.0312" },    }  ]        var client = {}    client.x = '-7514.48'  client.y = '-9443.54'  client.z = '-183.969'    var distances = []    (var = 0; < houses.length; i++) {        var house = houses[i]        var distance_between_house_min_max = math.sqrt(((house.min.x - house.max.x)*(house.min.x - house.max.x)) + ((house.min.y - house.max.y)*(house.min.y - house.max.y)) + ((house.min.z - house.max.z)*(house.min.z - house.max.z)));        // here take house.max , house.min in order clients distance house        var distance_of_client_to_house = math.sqrt(((client.x - house.max.x)*(client.x - house.max.x)) + ((client.y - house.max.y)*(client.y - house.max.y)) + ((client.z - house.max.z)*(client.z - house.max.z)));        console.log("distance " + house.name + " is: " + distance_of_client_to_house)        distances.push({ house: house, distance: distance_of_client_to_house })    }    // order distances lowest distance    distances = distances.sort(function (a, b) {    return a.distance > b.distance  });    console.log("distances:")  console.log(distances)      

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approach 2: since stackoverflow not support node js modules, did not include approach in first place. that's why headed approach 1 strings instead of 'real' vector objects.

basically, in approach use vec3 node js module offers vector manipulation.

var vector = require("vec3").vec3  var houses = [   {     "max": new vector(-7839.9688, -7469.0312, 215.537),     "name": "house 1",     "min": new vector(-7112.0312, -7932.9692, 72.0312)   },    {     "max": new vector(-6380.0312, -9586.1963, 372.1475),     "name": "house 3",     "min": new vector(-6764.2441, -9189.0312, 96.3953),   },   {     "max": new vector(-7747.1074, -8659.9023, 422.2812),     "name": "house 2",     "min": new vector(-6827.3853, -9668.9688, 72.0312),   } ]  var client = new vector(-7514.48, -9443.54, -183.969)  var distances = []  (var = 0; < houses.length; i++) {    var house = houses[i]    var distance_between_house_min_max = house.min.distanceto(house.max);    // here take house.max , house.min in order clients distance house    var distance_of_client_to_house = client.distanceto(house.max);    console.log("distance " + house.name + " is: " + distance_of_client_to_house)    distances.push({ house: house, distance: distance_of_client_to_house })  }  // order distances lowest distance  distances = distances.sort(function (a, b) {   return a.distance > b.distance });  console.log("distances:") console.log(distances) 

demo: https://tonicdev.com/stevemuster/57c3a52fee25751400967ddd

question: how can correctly guess houses client near to? open suggestions/hints. thank you.