python - Gunicorn giving syntax error for my configuration file -


my config file 

[loggers] keys=root, gunicorn.error, gunicorn.access  [handlers] keys=console, error_file, access_file  [formatters] keys=generic, access  [logger_root] level=info handlers=console  [logger_gunicorn.error] level=info handlers=error_file propagate=1 qualname=gunicorn.error  [logger_gunicorn.access] level=info handlers=access_file propagate=0 qualname=gunicorn.access  [handler_console] class=streamhandler formatter=generic args=(sys.stdout, )  [handler_error_file] class=logging.filehandler formatter=generic args=('/tmp/gunicorn.error.log',)  [handler_access_file] class=logging.filehandler formatter=access args=('/tmp/gunicorn.access.log',)  [formatter_generic] format=%(asctime)s [%(process)d] [%(levelname)s] %(message)s datefmt=%y-%m-%d %h:%m:%s class=logging.formatter  [formatter_access] format=%(message)s class=logging.formatter

my command execute 

gunicorn --env django_settings_module=myproject.settings myproject.wsgi --log-level debug --log-file=- -c file:gunicorn_log.conf

getting error 

failed read config file: gunicorn_log.conf traceback (most recent call last):   file "/home/jameel/django-env/local/lib/python2.7/site-packages/gunicorn/app/base.py", line 93, in get_config_from_filename     execfile_(filename, cfg, cfg)   file "/home/jameel/django-env/local/lib/python2.7/site-packages/gunicorn/_compat.py", line 91, in execfile_     return execfile(fname, *args)   file "gunicorn_log.conf", line 27     class=streamhandler          ^ syntaxerror: invalid syntax

i followed per example in github link

gunicorn config file looks this: https://github.com/benoitc/gunicorn/blob/master/examples/example_config.py

your file logger configuration file.

logger configuration passed --log-config parameter.


-

Comments

Post a Comment

Popular posts from this blog

amazon web services - S3 Pre-signed POST validate file type? -

i know it's possible put limit on file size content-length-range header. possible validate file type? https://docs.aws.amazon.com/amazons3/latest/dev/httppostforms.html#policyconditions i see there content-type header, if set say, audio/mp3 allow mp3 files , return error if file not mp3? i found previous question answers mention validating file size: s3 direct upload restricting file size , type you can specify content-type @ post request. you can specify @ signature, post must done content-type: { "expiration": "2007-12-01t12:00:00.000z", "conditions": [ {"acl": "public-read" }, {"bucket": "johnsmith" }, {"content-type: "audio/mp3"} ] } creating html form (using aws signature version 4) edit: @ previous question found, checking content-type.
Read more

c# - Check Keyboard Input Winforms -

i wondering if instead of doing this protected override void onkeydown(keyeventargs e) { if (e.keycode == keys.a) console.writeline("the key down."); } i set bool method , this: if(keydown(keys.a)) // whatever here i've been sitting here ages trying figure out how it. can't wrap head around it. in case wondering, plan call bool inside different method, check input. since want perform action after pressing key, using keydown event enough. but in cases suppose want check if specific key down in middle of process, can use getkeystate method way: [dllimport("user32.dll", charset = charset.auto, exactspelling = true)] public static extern short getkeystate(int keycode); public const int key_pressed = 0x8000; public static bool iskeydown(keys key) { return convert.toboolean(getkeystate((int)key) & key_pressed); } you should know, each time check key state using example iskeydown(keys.a) method returns true if ke...
Read more